Solution: det (A) = −5, and for n×n matrix adj (A) has determinant (det A)^ (n−1). Here n = 3, so det (B) = (−5)^ (2) = 25. For feedback or story ideas, reach us at [email protected] ...
Candidates preparing for JEE Advanced 2026 can download the official syllabus PDF from jeeadv.ac.in, released by IIT Roorkee.
The Joint Entrance Examination (JEE) Main 2025 Session 2 began on April 2, with Paper 1 (B.E./B.Tech) being conducted by the National Testing Agency (NTA). The first shift took place from 9:00 AM to ...
JEE Main 2025 Answer Key News Live: The National Testing Agency has released the provisional answer key at jeemain.nta.nic.in. JEE Main 2025 Answer Key News Live: National Testing Agency (NTA) has ...
New Delhi: The JEE Main examination dates for the academic session 2025-26 will be released soon on its official website. The Joint Entrance Examination (JEE (Main) comprises two papers. Paper 1 (B.E.
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